![]() ![]() To compute the absolute distance, it's the larger value minus the smaller value, so 46.8 to x is 46.8 − x and the distance from x to 14.9 is x − 14.9. ![]() That last paragraph may be a bit confusing, so let's compare it to a number line: The colder water goes up in temperature, so its Δt equals x − 14.9. The warmer water goes down from to 46.8 to x, so this means its Δt equals 46.8 − x. Solution Key Number One: We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using IS NOT the Δt, but the FINAL temperature. What that means is that only the specific heat equation will be involved This problem type becomes slightly harder if a phase change is involved. This is very, very important.ģ) The energy which "flowed" out (of the warmer water) equals the energy which "flowed" in (to the colder water) The warmer water will cool down (heat energy "flows" out of it).Ģ) The whole mixture will wind up at the SAME temperature. Forgive me if the points seem obvious:ġ) The colder water will warm up (heat energy "flows" into it). Go to calculating the final temperature when mixing water and a piece of metalĮxample #1: Determine the final temperature when 32.2 g of water at 14.9 ☌ mixes with 32.2 grams of water at 46.8 ☌.įirst some discussion, then the solution. Go to Mixing Two Amounts of Water: Problems 1 - 10 The Final Temp after Mixing Two Amounts of Water When Two Samples of Water are Mixed, what Final Temperature Results? ![]()
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